Boas pessoal tenho este código PHP para gerar gráficos com a libraria phpgraphlib e não me dá erro simplesmente mostra-me uma imagem no lado superior esquerdo do browser o código que tenho é este, espero que me possam ajudar:
<?php
include("graph\phpgraphlib.php");
$graph=new PHPGraphLib(550,350);
$link = mysql_connect('localhost', 'username', 'password')
or die('Could not connect: ' . mysql_error());
mysql_select_db('bdd') or die('Could not select database');
$dataArray=array();
//get data from database
$sql="SELECT ano, resultado AS 'count' FROM valores GROUP BY ano";
$result = mysql_query($sql) or die('Query failed: ' . mysql_error());
if ($result) {
while ($row = mysql_fetch_assoc($result)) {
$dated=$row['ano'];
// $dated = strtoint($dated)
// $count=$row["count"];
//add to data areray
$dataArray[$dated] = $row['resultado'];
}
}
//configure graph
$graph->addData($dataArray);
$graph->setTitle("Resultados das vendas");
$graph->setGradient("lime", "green");
$graph->setBarOutlineColor("black");
$graph->createGraph();
?>
<html>
<h3>This is where I want to display my graph</h3>
<img src="tt.php" />
</html>
<?php
include("graph\phpgraphlib.php");
$graph=new PHPGraphLib(550,350);
$link = mysql_connect('localhost', 'username', 'password')
or die('Could not connect: ' . mysql_error());
mysql_select_db('bdd') or die('Could not select database');
$dataArray=array();
//get data from database
$sql="SELECT ano, resultado AS 'count' FROM valores GROUP BY ano";
$result = mysql_query($sql) or die('Query failed: ' . mysql_error());
if ($result) {
while ($row = mysql_fetch_assoc($result)) {
$dated=$row['ano'];
// $dated = strtoint($dated)
// $count=$row["count"];
//add to data areray
$dataArray[$dated] = $row['resultado'];
}
}
//configure graph
$graph->addData($dataArray);
$graph->setTitle("Resultados das vendas");
$graph->setGradient("lime", "green");
$graph->setBarOutlineColor("black");
$graph->createGraph();
?>
<html>
<h3>This is where I want to display my graph</h3>
<img src="tt.php" />
</html>
